# Elementary Number Theory Problems 3.3 Solution (David M. Burton's 7th Edition) - Q10

My Solution for "Establish that the sequence $$(n + 1)! - 2, (n + 1)! - 3, ... , (n + 1)! - (n + 1)$$ produces $n$ consecutive composite integers for $n > 2$."

Background

All theorems, corollaries, and definitions listed in the book's order:

**I will only use theorems or facts that are proved before this question**. So you will not see that I quote theorems or facts from the later chapters.

## Question

Establish that the sequence $$(n + 1)! - 2, (n + 1)! - 3, ... , (n + 1)! - (n + 1)$$ produces $n$ consecutive composite integers for $n > 2$.

## Solution

We rewrite the sequence as $(n + 1)! - i$, where $i \in \mathbb{Z}$ and $2 \leq i \leq n + 1$.

As $i \leq n + 1$, we know $i \mid (n + 1)!$. We also know $i \mid i$. By Theorem 2.2(g), $i \mid (n + 1)! - i$.

If $i = (n + 1)! - i$:

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