# Elementary Number Theory Problems 3.2 Solution (David M. Burton's 7th Edition) - Q11

My Solution for "If $p_{n}$ denotes the $n$th prime number, put $d_{n} = p_{n+1} - p_{n}$. An open question is whether the equation $d_{n} = d_{n + 1}$ has infinitely many solutions. Give five solutions."

## Table of Contents

Background

All theorems, corollaries, and definitions listed in the book's order:

**I will only use theorems or facts that are proved before this question**. So you will not see that I quote theorems or facts from the later chapters.

## Question

If $p_{n}$ denotes the $n$th prime number, put $d_{n} = p_{n+1} - p_{n}$. An open question is whether the equation $d_{n} = d_{n + 1}$ has infinitely many solutions. Give five solutions.

## Solution

(I wrote a program for this question.)

$d_{2} = p_{3} - p_{2} = 5 - 3 = 2$

$d_{3} = p_{4} - p_{3} = 7 - 5 = 2$

So, $d_{2} = d_{3}$.

$d_{15} = p_{16} - p_{15} = 53 - 47 = 6$

$d_{16} = p_{17} - p_{16} = 59 - 53 = 6$

So, $d_{15} = d_{16}$

$d_{36} = p_{37} - p_{36} = 157 - 151 = 6$

$d_{37} = p_{38} - p_{37} = 163 - 157 = 6$

So, $d_{36} = d_{37}$

$d_{39} = p_{40} - p_{39} = 173 - 167 = 6$

$d_{40} = p_{41} - p_{40} = 179 - 173 = 6$

So, $d_{39} = d_{40}$

$d_{46} = p_{47} - p_{46} = 211 - 199 = 12$

$d_{47} = p_{48} - p_{47} = 223 - 211 = 12$

So, $d_{46} = d_{47}$

**Read More:** All My Solutions for This Book

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